hdu2126—Buy the souvenirs(01背包方案数)

Problem Description
When the winter holiday comes, a lot of people will have a trip. Generally, there are a lot of souvenirs to sell, and sometimes the travelers will buy some ones with pleasure. Not only can they give the souvenirs to their friends and families as gifts, but also can the souvenirs leave them good recollections. All in all, the prices of souvenirs are not very dear, and the souvenirs are also very lovable and interesting. But the money the people have is under the control. They can’t buy a lot, but only a few. So after they admire all the souvenirs, they decide to buy some ones, and they have many combinations to select, but there are no two ones with the same kind in any combination. Now there is a blank written by the names and prices of the souvenirs, as a top coder all around the world, you should calculate how many selections you have, and any selection owns the most kinds of different souvenirs. For instance:

And you have only 7 RMB, this time you can select any combination with 3 kinds of souvenirs at most, so the selections of 3 kinds of souvenirs are ABC (6), ABD (7). But if you have 8 RMB, the selections with the most kinds of souvenirs are ABC (6), ABD (7), ACD (8), and if you have 10 RMB, there is only one selection with the most kinds of souvenirs to you: ABCD (10).

For the first line, there is a T means the number cases, then T cases follow.
In each case, in the first line there are two integer n and m, n is the number of the souvenirs and m is the money you have. The second line contains n integers; each integer describes a kind of souvenir.
All the numbers and results are in the range of 32-signed integer, and 0<=m<=500, 0

> File Name: hdu2126.cpp
> Author: ALex
> Mail: zchao1995@gmail.com
> Created Time: 2015年03月05日 星期4 21时04分58秒

#include <map>
#include <set>
#include <queue>
#include <stack>
#include <vector>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;

const double pi = acos(-1);
const int inf = 0x3f3f3f3f;
const double eps = 1e⑴5;
typedef long long LL;
typedef pair <int, int> PLL;

int dp[510];
int dp2[510];
int goods[35];

int main ()
int t;
int n, m;
scanf("%d", &t);
while (t--)
scanf("%d%d", &n, &m);
int all = 0;
for (int i = 1; i <= n; ++i)
scanf("%d", &goods[i]);
int tmp = m;
sort (goods + 1, goods + 1 + n);
for (int i = 1; i <= n; ++i)
if (tmp >= goods[i])
tmp -= goods[i];
if (!all)
printf("Sorry, you can't buy anything.
memset (dp, 0, sizeof (dp));
for (int i = 0; i <= m; ++i)
dp2[i] = 1;
for (int i = 1; i <= n; ++i)
for (int j = m; j >= goods[i]; --j)
if (dp[j] < dp[j - goods[i]] + 1)
dp[j] = dp[j - goods[i]] + 1;
dp2[j] = dp2[j - goods[i]];
else if (dp[j] == dp[j - goods[i]] + 1)
dp2[j] += dp2[j - goods[i]];
printf("You have %d selection(s) to buy with %d kind(s) of souvenirs.
, dp2[m], all);
return 0;

波比源码 – 精品源码模版分享 | www.bobi11.com
1. 本站所有资源来源于用户上传和网络,如有侵权请邮件联系站长!
2. 分享目的仅供大家学习和交流,您必须在下载后24小时内删除!
3. 不得使用于非法商业用途,不得违反国家法律。否则后果自负!
4. 本站提供的源码、模板、插件等等其他资源,都不包含技术服务请大家谅解!
5. 如有链接无法下载、失效或广告,请联系管理员处理!
6. 本站资源售价只是赞助,收取费用仅维持本站的日常运营所需!
7. 本站源码并不保证全部能正常使用,仅供有技术基础的人学习研究,请谨慎下载
8. 如遇到加密压缩包,请使用WINRAR解压,如遇到无法解压的请联系管理员!

波比源码 » hdu2126—Buy the souvenirs(01背包方案数)
赞助VIP 享更多特权,建议使用 QQ 登录